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10x^2=31x+62
We move all terms to the left:
10x^2-(31x+62)=0
We get rid of parentheses
10x^2-31x-62=0
a = 10; b = -31; c = -62;
Δ = b2-4ac
Δ = -312-4·10·(-62)
Δ = 3441
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-31)-\sqrt{3441}}{2*10}=\frac{31-\sqrt{3441}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-31)+\sqrt{3441}}{2*10}=\frac{31+\sqrt{3441}}{20} $
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